107404domain: NAppears in sequencesa(n) = min{ m : sum_{n <= i <= m} 1/p_i > 1}, where p_i is the i-th prime = A000040(i).at n=39A092325Logarithmic transform of Fibonacci numbers A000045.at n=11A112005a(n) = 2^n * [x^n] Product_{k>=1} 1/(1 - 2*x^k)^(1/2).at n=9A370713