1063532

Appears in sequences

• Numerators of continued fraction convergents to sqrt(281).at n=12A041528
• Let p(n) be the n-th prime congruent to 1 mod 4. Then a(n) = the least m for which m^2+1=p(n)*k^2 has a solution.at n=27A094048
• Value x in the solution of x^2-D*y^2=-1 as D runs through A003654.at n=46A249021