1046528
domain: N
Appears in sequences
- Nonsquarefree numbers m such that rad(m+1)=rad(m)+1, where rad(m)=A007947(m) is the squarefree kernel of m.at n=6A081084
- Numbers m such that A007947(m) = A007947(k) and A007947(m+1) = A007947(k+1), for some k < m.at n=9A087914
- a(n) = 4a(n-1) - 6a(n-2) + 4a(n-3), n > 3; a(0) = 3, a(1) = 2, a(2) = a(3) = 0.at n=20A133209
- a(n) = (n^2-1)^2-1.at n=32A178392
- Number of bitstrings of length n (with at least two runs) where the last two runs have different lengths.at n=19A208901
- Total area of all squares and rectangles after 2^n stages in the toothpick structure of A139250, assuming the toothpicks have length 2.at n=10A211012
- Number of active (ON, black) cells at stage 2^n-1 of the two-dimensional cellular automaton defined by "Rule 261", based on the 5-celled von Neumann neighborhood.at n=9A271061
- Number of active (ON, black) cells at stage 2^n-1 of the two-dimensional cellular automaton defined by "Rule 657", based on the 5-celled von Neumann neighborhood.at n=9A273335
- Number of active (ON, black) cells at stage 2^n-1 of the two-dimensional cellular automaton defined by "Rule 721", based on the 5-celled von Neumann neighborhood.at n=9A273446
- Decimal representation of the x-axis, from the left edge to the origin, of the n-th stage of growth of the two-dimensional cellular automaton defined by "Rule 65", based on the 5-celled von Neumann neighborhood.at n=19A278755
- Decimal representation of the diagonal from the origin to the corner of the n-th stage of growth of the two-dimensional cellular automaton defined by "Rule 182", based on the 5-celled von Neumann neighborhood.at n=21A286410
- Decimal representation of the diagonal from the origin to the corner of the n-th stage of growth of the two-dimensional cellular automaton defined by "Rule 315", based on the 5-celled von Neumann neighborhood.at n=22A287625
- a(n) = 2*a(n-1) + 2*a(n-2) - 4*a(n-3), a(1) = 0, a(2) = 0, a(3) = 8.at n=18A297619
- Pairs of integers (k, m) ordered by m with 1 < k < m such that k has the same prime divisors as m, and, k+1 has the same prime divisors as m+1.at n=19A343101