104484802057domain: NAppears in sequencesa(n) = prime(2^n).at n=32A033844Numbers that begin a run of consecutive integers k such that PrimePi(k) divides 2^k.at n=31A073799a(n) = prime(2^(2^n)).at n=5A095124a(n) = prime(4^n).at n=16A119772(16^n)-th prime.at n=8A119777