1018249595domain: NAppears in sequencesa(n) = (1/4)* L(n)^2 * F(n+1)^2 * L(n-1) * F(n+2), where F(n) and L(n) are the Fibonacci and Lucas numbers, respectively.at n=8A163197Sum of the cubes of the first n even-indexed Fibonacci numbers, minus 1.at n=8A163199