101675

Appears in sequences

• a(n) = (n + 1!)*(n^2 + 2!)*(n^3 + 3!)/3!.at n=9A131682
• Let r_1 = 1. Let r_{m+1} = r_1 + 1/(r_2 + 1/(r_3 +...(r_{m-1} + 1/r_m)...)), a continued fraction of rational terms. Then a(n) is the number of (positive integer) terms in the simple continued fraction of r_n.at n=19A138743