-4095
domain: Z
Appears in sequences
- sin(arctan(x)+arcsin(x))=2*x-9/3!*x^3+105/5!*x^5-4095/7!*x^7...at n=3A012986
- Expansion of e.g.f.: sech(log(x+1)-tan(x))=1-3/4!*x^4-90/6!*x^6+168/7!*x^7-4095/8!*x^8...at n=8A013245
- Expansion of e.g.f.: sech(log(x+1)-arctan(x))=1-3/4!*x^4+40/5!*x^5-250/6!*x^6+840/7!*x^7...at n=8A013257
- sech(log(x+1)-arctanh(x))=1-3/4!*x^4-90/6!*x^6-4095/8!*x^8...at n=4A013304
- a(n) = 1 - n^3.at n=16A024001
- a(n) = 1 - n^4.at n=8A024002
- a(n) = 1 - n^6.at n=4A024004
- a(n) = 1 - n^12.at n=2A024010
- a(n) = A023194 - A062700(n). Negative values of A071166(m) = m-A006530(A000203(m)) differences. In these cases m is square number from A023194.at n=11A071167
- Expansion of 1/((1 - 2*x + 2*x^2)*(1-x)).at n=22A077860
- Expansion of 1/((1 - 2*x + 2*x^2)*(1-x)).at n=23A077860
- Expansion of (1-x)^(-1)/(1+2*x^2-2*x^3).at n=19A077891
- Odd-indexed terms of the binomial transform equals 1 and the even-indexed terms of the second binomial transform equals 1.at n=12A090158
- G.f. A(x) has the property that the first (n+1) terms of A(x)^(n+1) form the n-th row polynomial R_n(y) of triangle A097181 and satisfy R_n(1/2) = 8^n for all n>=0.at n=22A097182
- Expansion of g.f.: (1-3*x+x^2)/((1-x)*(1+x)*(1-2*x+2*x^2)).at n=23A106664
- Inverse of a triangle of pyramidal numbers.at n=66A110814
- Triangular table of coefficients of Laguerre-Sonin polynomials n!*2^n*Lag(n,x/2,1/2) of order 1/2.at n=33A130757
- a(n) = A135574(n+1) - 2*A135574(n).at n=12A135575
- Triangle T(n, k, q) = c(n,q)/( c(k,q)*c(n-k,q) ), where c(n, q) = Product_{j=1..n} f(n, q), f(n, q) = ( (1-q^n)*(1+(-1)^n) + n!*(1-(-1)^n) )/2, and q = 4, read by rows.at n=22A172429
- Triangle T(n, k, q) = c(n,q)/( c(k,q)*c(n-k,q) ), where c(n, q) = Product_{j=1..n} f(n, q), f(n, q) = ( (1-q^n)*(1+(-1)^n) + n!*(1-(-1)^n) )/2, and q = 4, read by rows.at n=26A172429