-389
domain: Z
Appears in sequences
- First order recursion: a(0) = 1; a(n) = phi(n) - a(n-1) = A000010(n) - a(n-1).at n=64A083239
- a(n) = -n^2 + 9*n + 53.at n=26A126665
- Smallest error in trying to solve n^3 = x^3 + y^3. That is, for each n, find positive integers x <= y < n such that | n^3 - x^3 - y^3 | is minimal and let a(n) := n^3 - x^3 - y^3.at n=69A135998
- An infinite sum polynomial triangular sequence of coefficients that gives a LerchPhi polynomial: p(x,n)=(1 - x)^(n + 1)*Sum[(n + k)^n*x^k, {k, 0, Infinity}]=(1+x)^n*LerchPhi[x,-n,n].at n=13A142158
- Inverse binomial transform of A014217.at n=10A142585
- Numerator of Laguerre(n, 6).at n=10A160631
- Sequence defined by the recurrence formula a(n+1) = sum(a(p)*a(n-p)+k,p=0..n)+l for n>=1, with here a(0)=1, a(1)=1, k=-2 and l=0.at n=7A177111
- Expansion of (x^2+1)/(x^4+2*x^3-2*x+1).at n=12A188802
- Values of n such that L(5) and N(5) are both prime, where L(k) = (n^2+n+1)*2^(2*k) + (2*n+1)*2^k + 1, N(k) = (n^2+n+1)*2^k + n.at n=21A226925
- a(n) = a(n-1) + a(n-2) - 2^(n-1) with a(0)=a(2)=0, a(1)=-a(3)=1, a(4)=-5.at n=9A227200
- Values of n such that L(16) and N(16) are both prime, where L(k) = (n^2+n+1)*2^(2*k) + (2*n+1)*2^k + 1, N(k) = (n^2+n+1)*2^k + n.at n=2A227519
- Triangle read by rows: T(n,k) is the coefficient A_k in the transformation Sum_{k=0..n} x^k = Sum_{k=0..n} A_k*(x+3*(-1)^k)^k.at n=25A249268
- a(n) = nearest integer to n^2 * sin(sqrt(n)).at n=20A274088
- Take alternate terms of A274088 and A274090.at n=40A274091
- a(n) = nearest integer to k^2*sin(sqrt(k)+j*Pi/2) where n = 3*k+j, 0<=j<3.at n=60A274092
- G.f.: Im((i*x; x)_inf), where (a; q)_inf is the q-Pochhammer symbol, i = sqrt(-1).at n=48A292043
- G.f.: Im((i*x; x)_inf), where (a; q)_inf is the q-Pochhammer symbol, i = sqrt(-1).at n=55A292043
- Sum of n-th powers of the roots of x^3 + 8*x^2 + 5*x - 1.at n=3A322461
- a(n) = A134028(A323782(n)): Primes and negated primes such that the reverse of the balanced ternary representation is a prime.at n=46A323783
- a(n) = n! * Sum_{k=0..floor(n/2)} (-1)^k / (n-2*k)!.at n=6A337749