-318
domain: Z
Appears in sequences
- Expansion of Product_{m>=1} (1+q^m)^(-3).at n=17A022598
- Row sums of triangle K(m, n), inverse to triangle T(m,n) in A020921.at n=8A038200
- McKay-Thompson series of class 14b for Monster.at n=58A058506
- McKay-Thompson series of class 20D for Monster.at n=23A058553
- McKay-Thompson series of class 30a for Monster.at n=16A058619
- a(n+1) = a(n) - a(floor(n/2)), with a(0)=0, a(1)=1.at n=45A062187
- a(n) = floor( prime(n-1)*A036263(n-2)/ A001223(n-1)).at n=29A094900
- a(n) = 2*a(n-1) - 3*a(n-2) + 2*a(n-3) with a(0) = 1, a(1) = 5, a(2) = 6.at n=14A105577
- a(n+3) = a(n) - a(n+1) - a(n+2); a(0) = -5, a(1) = 6, a(2) = 0.at n=14A105580
- Let c(n) = x^(2^n-1)*(1-x^(2^n)), g(n) = 1 + x^(2^n-1) + x^(2^n), h(n) = Product_{i=1..n} g(i); then use g.f. (1+2*x) - Sum_{n>=1} c(n)/h(n).at n=44A151684
- A triangle sequence from matrix polynomials of a three symbol type {0, 1, -1}: c(i,k)= Floor[Mod[i/2^k, 2]]; M(d)=Table[If[Sum[c(n, k)*c(m, k), {k, 0, d - 1}] == 0, 1, If[Sum[c(n, k)*c(m, k), {k, 0, d - 1}] == 1, -1, 0]], {n, 0, d - 1}, {m, 0, d - 1}].at n=50A158417
- Hankel transform of A174399.at n=13A174400
- a(n) = A218542(n) - A218543(n).at n=16A257259
- G.f. A(x,y) satisfies: A(x,y) = x*y + 1/A(x,x*y), with A(0,y) = 1.at n=174A275760
- Expansion of r(q)^3 / r(q^3) in powers of q where r() is the Rogers-Ramanujan continued fraction.at n=24A285628
- Expansion of 1/(1 + x/(1 + x^8/(1 + x^27/(1 + x^64/(1 + x^125/(1 + ... + x^(k^3)/(1 + ...))))))), a continued fraction.at n=45A291169
- The arithmetic function uhat(n,1,8).at n=52A291502
- Expansion of Product_{k>=1} (1 - 3*x^k).at n=28A292128
- L.g.f.: log(1 + Sum_{k>=1} prime(k)*x^k) = Sum_{n>=1} a(n)*x^n/n.at n=15A303073
- Expansion of Product_{k>=1} ((1 - 2*x^k)/(1 + 2*x^k))^(1/2).at n=11A303345