-2187
domain: Z
Appears in sequences
- Expansion of bracket function.at n=13A000748
- a(n) = Sum_{j=0..floor(n/3)} (-1)^j*binomial(n,3*j).at n=16A057681
- Triangle, read by rows, where the n-th row lists the (2*n+1) coefficients of (1 + x - 3*x^2)^n.at n=63A084614
- Expansion of (1-3*x+12*x^2)/((1-3*x)*(1+3*x)).at n=7A091103
- A transform of the Jacobsthal numbers.at n=17A103312
- Triangle T, read by rows, where matrix power T^3 has powers of 3 in the secondary diagonal: [T^3](n+1,n) = 3^(n+1), with all 1's in the main diagonal and zeros elsewhere.at n=18A117252
- Expansion of (1 - 3x)/(1 + 3*x^2).at n=13A128019
- Expansion of (1 - 3x)/(1 + 3*x^2).at n=14A128019
- a(n) = the numerator of b(n): {b(n)} is such that the continued fraction (of rational terms) [b(1);b(2),...,b(n)] equals the n-th prime, for every positive integer n.at n=26A128270
- a(n) = the numerator of b(n): {b(n)} is such that the continued fraction (of rational terms) [b(1);b(2),...,b(n)] equals the n-th prime, for every positive integer n.at n=28A128270
- Triangular sequence produced from symmetrical power of two matrices of the general type: M={{1, 2, 4, 8}, {2, 1, 2, 4}, {4, 2, 1, 2}, {8, 4, 2, 1}}.at n=36A129964
- A Chebyshev polynomial triangle of the first kind defined by T(n+1,x) = 3x*T(n,x) - T(n-1,x).at n=21A136159
- Inverse binomial transform of A140962.at n=9A141413
- Triangle T(n,k) read by rows: T(n,n) = -1, T(n,0) = 3^(n - 1), T(n,k) = -3^(n - k - 1), 1 <= k <= n - 1.at n=46A152570
- Triangle T(n,k) read by rows: T(n,n) = -1, T(n,0) = 3^(n - 1), T(n,k) = -3^(n - k - 1), 1 <= k <= n - 1.at n=57A152570
- Scaled row sum zero vector recursion:s=3; v(n)={s^(n+1),s^(n+1)-Sum[s^i,{i,2,n}],s^n,...,-1}.at n=47A152860
- G.f.: A(x) = 1 + x/exp( Sum_{k>=1} (A((-1)^k*x) - 1)^k/k ).at n=16A157674
- a(n) = 3*a(n-2) for n > 2; a(1) = 3, a(2) = -1.at n=15A162852
- Fibonacci matrix read by antidiagonals. (Inverse of A136158.)at n=29A164948
- Villegas-Zagier polynomials (listing coefficients from lowest to highest degree).at n=64A166243