-1400
domain: Z
Appears in sequences
- Expansion of Product (1 - x^k)^8 in powers of x.at n=30A000731
- Expansion of e.g.f.: log(arctanh(x)+cos(x)) = x-2/2!*x^2+7/3!*x^3-28/4!*x^4+193/5!*x^5...at n=6A013181
- McKay-Thompson series of class 10c for Monster.at n=39A058204
- Triangle of trinomial logarithmic coefficients: A027907(n,k) = Sum_{i=0..k} T(k,i)*n^i/k!.at n=41A136590
- Expansion of q^(-1/3) * (eta(q)^8 + 8 * eta(q^4)^8) in powers of q^2.at n=15A153728
- Expansion of q^(-1/3) * (eta(q)^8 + 32 * eta(q^4)^8) in powers of q.at n=30A153729
- Expansion of f(q)^8 in powers of q where f() is a Ramanujan theta function.at n=30A161969
- Totally multiplicative sequence with a(p) = 10*(p-3) for prime p.at n=33A167320
- Totally multiplicative sequence with a(p) = (p-3)*(p+3) = p^2-9 for prime p.at n=33A167362
- Expansion of g.f.: 2^(floor((n+1)/2))*n!*(1-y)^(n+1)*f(x, y, m), where f(x, y, m) = 2^(m+1)*exp(2^m*t)/((1-y*exp(t))*(1 + (2^(m+1)-1)*exp(2^m*t))), and m = 1.at n=26A171695
- Triangle in which row n has the n*(n+1)/2 elements of the lower triangular part of the inverse of the n-th order Hilbert matrix.at n=26A189765
- Expansion of q^(-1/4) * eta(q)^8 * eta(q^4)^2 / eta(q^2)^5 in powers of q.at n=37A244276
- First differences of number of active (ON, black) cells in n-th stage of growth of two-dimensional cellular automaton defined by "Rule 163", based on the 5-celled von Neumann neighborhood.at n=27A270456
- Determinant of the inverse of the matrix A_n, where A_n is the n X n matrix defined by A_n[i,j] = 1/C(i+j-2) for 1 <= i,j <= n, and C(k) is the k-th Catalan number (A000108).at n=2A296056
- Triangle read by rows in which row n gives coefficients of polynomial f_n(x) of degree less than n that satisfies Integral_{x=0..1} g(t - x) * f_n(x) dx = g(t) for any polynomial g(x) of degree less than n.at n=13A303699
- Triangular array read by rows: row n shows the coefficients of this polynomial of degree n: (1/n!)*(numerator of n-th derivative of 1)/(1-x-2x^2).at n=24A328650
- G.f.: 1 + 1*x/(1 + 2*x^2/(1 + 3*x^3/(1 + 4*x^4/(1 + 5*x^5/(1 + ...))))).at n=19A343468
- Dirichlet inverse of A341528, where A341528(n) = n * sigma(A003961(n)), and A003961 is fully multiplicative with a(prime(i)) = prime(i+1).at n=49A378228
- a(n) = Sum_{k=0..n} k^5 * (-1)^k * 3^(n-k) * binomial(n,k).at n=5A383152