-1274
domain: Z
Appears in sequences
- McKay-Thompson series of class 12G for Monster.at n=28A058485
- a(n) = (n+1)*(2-n)/2.at n=51A080956
- G.f. satisfies: A(x) = 1/(1 + x*A(x^8)) and also the continued fraction: 1 + x*A(x^9) = [1; 1/x, 1/x^8, 1/x^64, 1/x^512, ..., 1/x^(8^(n-1)), ...].at n=51A101918
- Expansion of f(-q)^2*P(q) in powers of q.at n=53A122163
- Totally multiplicative sequence with a(p) = 7*(p-3) for prime p.at n=57A167317
- Triangle T(n, k, q) = (1-q^n)*( binomial(n, k) - 1 ) + 1, with q = 4, read by rows.at n=12A174720
- Triangle T(n, k, q) = (1-q^n)*(1/k)*binomial(n-1, k-1)*binomial(n, k-1) - (1-q^n) + 1, for q = 4, read by rows.at n=7A174733
- Triangle T(n, k, q) = (1-q^n)*(1/k)*binomial(n-1, k-1)*binomial(n, k-1) - (1-q^n) + 1, for q = 4, read by rows.at n=8A174733
- Expansion of g.f. 1+x+(1+3*x+x^2)/(1+x)^3.at n=50A201163
- Triangle, read by rows of n^2 terms, where row n equals the coefficients in the series reversion of the function G(y,n)-1 such that: y = Sum_{m>=1} 1/G(y,n)^(2*n*m) * Product_{k=1..m} (1 - 1/G(y,n)^(2*k-1)).at n=25A214690
- a(n) = Sum_{k=0..floor(n/4)} (-1)^k * binomial(n+3,4*k+3) * Catalan(k).at n=10A360050